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Algebra II Lesson 5.3 "Transforming Parabolas (Vertex Form)"

Algebra II Lesson 5.3 "Transforming Parabolas (Vertex Form)"

Author: Chad Bray

To graph a parabola from the vertex form of a quadratic function

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Video of the Lesson

You will want to have a graphing calculator available to use during the lesson. Also, pay close attention to the similarities between quadratic functions (parabolas) and the absolute value functions we studied back in Chapter 2.

PowerPoint of the Lesson


1) Complete the "On Your Own" problem from the lesson.

2) Write a summary of the lesson. Use proper grammar, spelling, punctuation and complete sentences.

In Class

We will be working on the assignment listed below the next time we meet in class. You may get started on it ahead of time if you'd like. There is graph paper available in my room. Stop by to pick some up if you want it.

Pg. 255-257 #1-12, 21-26, 40-42, 77

Questions and Answers

  • kaylee
    Answer 1
    kaylee — over 1 year ago

    How do you graph the equation of the parabola in vertex form?

      Chad Bray answered over 1 year ago

      Sorry for the late response, but I haven't been on sophia.org for a while. Use the numbers in the equation to determine where to start your parabola. For example, in the equation y = 2(x - 3)^2 + 4 the 3 inside the parenthesis tells me to shift right 3 and the 4 tells me to shift up 4. That is where the vertex of the parabola lies and where you should start the graph. The axis of symmetry is a vertical line through the vertex. Then, find the y-intercept by plugging 0 into the equation. After that, reflect that y-intercept across your axis of symmetry to find a 3rd point. You now have enough points to draw your parabola.

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