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Solving Rational Equations

Author: Sophia

what's covered
In this lesson, you will learn how to determine an equivalent rational expression by finding the least common denominator. Specifically, this lesson will cover:

Table of Contents

1. Rational Equations and Extraneous Solutions

A rational equation is an equation that contains at least one rational expression. Recall that a rational expression can also be referred to as an algebraic fraction. In other words, one of the terms has a variable in the denominator.

There is a very important implication when a variable is in the denominator of an expression or equation. Dividing any quantity by zero leads to an undefined value, so whenever the denominator is equal to zero, the equation is undefined. Sometimes, when solving rational equations, we can make all the right moves algebraically, but the solution we get for our variable makes our denominator equal to zero. These solutions are known as extraneous solutions.

hint
When solving rational equations, always check to make sure the solution does not make the denominator equal zero. If it does, the solution is extraneous, and should not be included in your final answer as a solution to the rational equation.

A useful strategy in solving rational equations is to rewrite the equation so that every term has a common denominator. The reason for this is that once all terms are written to have a common denominator, we can create an equation with just the numerators.

EXAMPLE

Find the solution to fraction numerator 2 x over denominator x plus 1 end fraction plus fraction numerator 3 over denominator x plus 1 end fraction equals fraction numerator x minus 4 over denominator x plus 1 end fraction.

Since all the fractions have the same denominator, we can just focus on the numerators.

fraction numerator 2 x over denominator x plus 1 end fraction plus fraction numerator 3 over denominator x plus 1 end fraction equals fraction numerator x minus 4 over denominator x plus 1 end fraction Use numerators only
2 x plus 3 equals x minus 4 Subtract 3 from both side
2 x equals x minus 7 Subtract x from both sides
x equals short dash 7 Our solution

Because each term in the rational equation has the same expression for its denominator, this also represents a solution to the rational equation. The only thing we need to do is check to make sure that when x equals short dash 7, we never have a denominator of zero in any of the terms. Since the denominator is x plus 1, and short dash 7 plus 1 is equal to -6, which is non-zero, we can say that x equals short dash 7 is the solution to this rational equation.

term to know
Rational Equation
An equation with a least one rational expression.


2. Finding the Least Common Denominator

Now that we have a useful strategy for solving rational functions, let's talk about the processes for creating terms with common denominators. The easiest method to find a common denominator between rational expressions is to multiply the terms in the denominator together.

EXAMPLE

Find a common denominator between these algebraic fractions:

fraction numerator 1 over denominator x squared plus 2 end fraction space space space space space space space space space space fraction numerator x plus 3 over denominator x end fraction space space space space space space space space space space x over 5

To find a common denominator, we would multiply each denominator, x squared plus 2, x, and 5, together.

open parentheses x squared plus 2 close parentheses times x times 5 equals open parentheses x squared plus 2 close parentheses times 5 x equals x squared times 5 x plus 2 times 5 x equals 5 x cubed plus 10 x

The common denominator is 5 x cubed plus 10 x.

This method works for all cases, but it can get a bit messy sometimes with algebraic fractions. One strategy is to find the lowest common denominator by factoring each expression and multiply all of the distinct factors.

EXAMPLE

Find the least common denominator between these algebraic fractions:

fraction numerator 4 over denominator x open parentheses x plus 2 close parentheses end fraction space space space space space space space space space space fraction numerator x minus 8 over denominator 3 x end fraction space space space space space space space space space space fraction numerator x over denominator x plus 2 end fraction

First, factor each denominator as much as you can:

fraction numerator 4 over denominator x open parentheses x plus 2 close parentheses end fraction space space space space space space space space space space fraction numerator x minus 8 over denominator 3 times x end fraction space space space space space space space space space space fraction numerator x over denominator open parentheses x plus 2 close parentheses end fraction

Now that we've factored each denominator as much as we can, we're going to look at the greatest number of times each factor is used. Let's first look at x, which is used once, so we're going to include that as part of the lowest common denominator:

Next, look at open parentheses x plus 2 close parentheses. This is used once in the first fraction and once in the third fraction, so the greatest number of times it is used is once. So open parentheses x plus 2 close parentheses will also be included in the lowest common denominator:

The next factor is 3, which is used at most once in any fraction, so we will include a 3 in the lowest common denominator:

lowest space common space denominator equals x times open parentheses x plus 2 close parentheses times 3

We can rewrite this as:

lowest space common space denominator equals 3 x open parentheses x plus 2 close parentheses

Once we have our common denominator, we can solve for equation by following these steps:

  1. Multiply both the numerator and the denominator of the first fraction by the denominator of both the second fraction and third fraction.
  2. Repeat the process with the second fraction: multiply both the numerator and the denominator of the second fraction by the denominator of the first fraction and third fraction.
  3. Repeat for the third fraction; multiply both the numerator and the denominator of the third fraction by the denominator of the first fraction and second fraction.
  4. Add or subtract numerators and keep the denominator the same.

3. Solving Rational Equations using a Common Denominator

Let's solve the following rational equation using our common denominator strategy:

EXAMPLE

Find the solution to fraction numerator 1 over denominator x minus 4 end fraction plus 5 over x equals 4 over 3.

First, we need to find a common denominator. Luckily for us, each denominator is already factorized, so the least common factor is the product of the 3 denominators:

left parenthesis x minus 4 right parenthesis left parenthesis x right parenthesis left parenthesis 3 right parenthesis equals 3 x squared minus 12 x

The tricky part is now adjusting our numerators to the original fractions, in order to be equivalent with a new denominator. To do this, let's express each part of the fraction in factored form. This will help identify which factors need to be attached to the numerator:

fraction numerator 1 over denominator x minus 4 end fraction The denominator needs factors open parentheses 3 close parentheses and open parentheses x close parentheses; multiply both numerator and denominator
fraction numerator 1 open parentheses 3 close parentheses open parentheses x close parentheses over denominator open parentheses x minus 4 close parentheses open parentheses 3 close parentheses open parentheses x close parentheses end fraction Evaluate multiplication
fraction numerator 3 x over denominator 3 x squared minus 12 x end fraction Equivalent fraction to fraction numerator 1 over denominator x minus 4 end fraction


5 over x The denominator needs factors open parentheses 3 close parentheses and open parentheses x minus 4 close parentheses; multiply both numerator and denominator
fraction numerator 5 open parentheses 3 close parentheses open parentheses x minus 4 close parentheses over denominator x open parentheses 3 close parentheses open parentheses x minus 4 close parentheses end fraction Evaluate multiplication
fraction numerator 15 x minus 60 over denominator 3 x squared minus 12 x end fraction Equivalent fraction to 5 over x


4 over 3 The denominator needs factors open parentheses x close parentheses and open parentheses x minus 4 close parentheses; multiply both numerator and denominator
fraction numerator 4 open parentheses x close parentheses open parentheses x minus 4 close parentheses over denominator 3 open parentheses x close parentheses open parentheses x minus 4 close parentheses end fraction Evaluate multiplication
fraction numerator 4 x squared minus 16 x over denominator 3 x squared minus 12 x end fraction Equivalent fraction to 4 over 3

Notice how we multiplied each fraction by the other denominators. Now we can ignore the denominator (the expression we worked so hard to find!) and create an equation with no denominator at all:

fraction numerator 1 over denominator x minus 4 end fraction plus 5 over x equals 4 over 3 Multiply each fraction by the other denominators
fraction numerator 1 open parentheses 3 close parentheses open parentheses x close parentheses over denominator open parentheses x minus 4 close parentheses open parentheses 3 close parentheses open parentheses x close parentheses end fraction plus fraction numerator 5 open parentheses 3 close parentheses open parentheses x minus 4 close parentheses over denominator x open parentheses 3 close parentheses open parentheses x minus 4 close parentheses end fraction equals fraction numerator 4 open parentheses x close parentheses open parentheses x minus 4 close parentheses over denominator 3 open parentheses x close parentheses open parentheses x minus 4 close parentheses end fraction Evaluate multiplication
fraction numerator 3 x over denominator 3 x squared minus 12 x end fraction plus fraction numerator 15 x minus 60 over denominator 3 x squared minus 12 x end fraction equals fraction numerator 4 x squared minus 16 x over denominator 3 x squared minus 12 x end fraction Create equation with just numerators; ignore denominators
3 x plus open parentheses 15 x minus 60 close parentheses equals 4 x squared minus 16 x Equation with just numerators

This is actually a quadratic equation we can solve using the quadratic formula x equals fraction numerator short dash b plus-or-minus square root of b squared minus 4 a c end root over denominator 2 a end fraction, once we set one side of the equation equal to zero:

3 x plus open parentheses 15 x minus 60 close parentheses equals 4 x squared minus 16 x Combine 3x and 15x on the left side
18 x minus 60 equals 4 x squared minus 16 x Subtract 18x and add 60 to both sides
0 equals 4 x squared minus 16 x minus 18 x plus 60 Combine -16x and -18x on the right side
0 equals 4 x squared minus 34 x plus 60 Identify coefficients a comma b, and c
a equals 4 comma space b equals short dash 34 comma space c equals 60 Plug these values into quadratic formula
x equals fraction numerator short dash open parentheses short dash 34 close parentheses plus-or-minus square root of open parentheses short dash 34 close parentheses squared minus 4 open parentheses 4 close parentheses open parentheses 60 close parentheses end root over denominator 2 open parentheses 4 close parentheses end fraction Evaluate
x equals 2.5 comma space x equals 6 Our solutions

Be sure to plug in 2.5 and 6 into all denominators from our original rational equation. If either 2.5 or 6 makes one of the denominators equal to zero, we have an extraneous solution.

fraction numerator 1 over denominator x minus 4 end fraction plus 5 over x equals 4 over 3 Plug in 2.5 for x
fraction numerator 1 over denominator 2.5 minus 4 end fraction plus fraction numerator 5 over denominator 2.5 end fraction equals 4 over 3 Evaluate
fraction numerator 1 over denominator short dash 1.5 end fraction plus fraction numerator 5 over denominator 2.5 end fraction equals 4 over 3 Plugging 2.5 in for x does NOT result in any denominator of zero, so this is NOT an extraneous solution


fraction numerator 1 over denominator x minus 4 end fraction plus 5 over x equals 4 over 3 Plug in 6 for x
fraction numerator 1 over denominator 6 minus 4 end fraction plus 5 over 6 equals 4 over 3 Evaluate
1 half plus 5 over 6 equals 4 over 3 Plugging 6 in for x does NOT result in any denominator of zero, so this is NOT an extraneous solution

Since no denominator equals 0 at x equals 2.5 or x equals 6, there are no extraneous solutions to the rational equation.

summary
There are some cases where rational equations have extraneous solutions. If a potential solution makes the denominator of a rational expression equal to 0, then the solution is extraneous. We can solve a rational equation by finding the least common denominator. The easiest method is to multiply all the denominators together. Then, because the denominators are the same, you can write and solve a rational equation using just the numerators of each fraction.

Source: ADAPTED FROM "BEGINNING AND INTERMEDIATE ALGEBRA" BY TYLER WALLACE, AN OPEN SOURCE TEXTBOOK AVAILABLE AT www.wallace.ccfaculty.org/book/book.html. License: Creative Commons Attribution 3.0 Unported License

Terms to Know
Rational Equation

An equation with at least one rational expression.